How would I find the first five terms of each sequence?
a1 = 2, a(n + 1) = an + 3
a1 = -4, a(n + 1 )= an + n^2
* I cant type downward exponents correctly
Arithmetic?
2015-09-25 10:40 pm
回答 (2)
2015-09-25 10:45 pm
✔ 最佳答案
First sequence:a1 = 2
a2 = a1 + 3 = 2 + 3 = 5
a3 = a2 + 3 = 5 + 3 = 8
a4 = a3 + 3 = 8 + 3 = 11
a5 = a4 + 3 = 11 + 3 = 14
Answer:
2, 5, 8, 11, 14
Second sequence:
a1 = -4
a2 = a1 + 1² = -4 + 1 = -3
a3 = a2 + 2² = -3 + 4 = 1
a4 = a3 + 3² = 1 + 9 = 10
a5 = a4 + 4² = 10 + 16 = 26
Answer:
-4, -3, 1, 10, 26
2015-09-25 10:46 pm
what do you mean by " downward exponents " ??
{ 2 , 5 , 8 , 11 , 14, 17...add 3 each time }
{ - 4 , -3 , 1 , 10 , 26 , 51 , ....}
{ 2 , 5 , 8 , 11 , 14, 17...add 3 each time }
{ - 4 , -3 , 1 , 10 , 26 , 51 , ....}
收錄日期: 2021-04-21 14:20:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150925144049AATxtWn