✔ 最佳答案
Specific latent heat of ice = 334000 J/kg
Specific heat capacity of water = 4200 J/(kg °C)
Specific heat capacity of coffee = 4000 J/(kg °C)
Assume that n ice cubes have to be added.
Heat gain by the ice cubes
= (Heat gain for melting ice) + (Heat gain to rise temperature 0°C to 10°C)
= (0.02n kg) × (334000 J/kg) + (0.02n kg) × [4200 J/(kg °C)] × (10 °C)
= 7520n J
Heat loss by the coffee
= (0.3 kg) × [4000 J/(kg °C)] × (40 - 10 °C)
= 36000 J
Heat gain by the ice cubes = Heat loss by the coffee
7520n = 36000
n = 4.8
At least 5 ice cubes have to be added. ...... (Ans)