25u^2-(9v^2-6v+1)?
回答 (2)
2015-09-23 12:13 pm
25u^2－(9v^2－6v+1)
=(5u)^2－(3v－1)^2
=(5u－3v+1)(5u+3v－1)
=(5u)^2－(3v－1)^2
=(5u－3v+1)(5u+3v－1)
2015-09-25 2:30 pm
25u^2 -(9v^2 -6v+1)
=25u^2 -(3v-1)^2
=[5u-(3v-1)][5u+(3v-1)]
=(5u-3v+1)(5u+3v-1)
=25u^2 -(3v-1)^2
=[5u-(3v-1)][5u+(3v-1)]
=(5u-3v+1)(5u+3v-1)
收錄日期: 2021-04-18 00:19:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150923031819AA2x7fr