A block with mass mA = 14.0 kg on a smooth horizontal surface is connected by a thin cord that passes over a pulley to a second block with mass mB = 5.0 kg which hangs vertically.
Determine the magnitude of the acceleration of the system.
A block with mass mA = 14.0 kg on a smooth horizontal surface...?
2015-09-17 6:57 pm
回答 (1)
2015-09-17 8:54 pm
motive force Fm = mb*g = 5*9.806 = 49.03 N
acceleration a = Fm/(ma+mb) = 49.03/19 = 2.5805 m/sec^2
acceleration a = Fm/(ma+mb) = 49.03/19 = 2.5805 m/sec^2
收錄日期: 2021-04-21 14:14:14
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