phys g field 問題?
2015-09-17 2:31 pm
A 31500-kg spaceship is halfway between the Earth and the Moon. Find the net gravitational force (in Newtons) of attraction exerted on the ship by the Earth and the Moon. (Given: Earth-moon distance = 3.84 x 108 m) Moon mass (kg): 7.36 x 10^22 radius
回答 (1)
2015-09-17 10:42 pm
m = 31500-kg spaceship is halfway between the Earth and the Moon. Find
the net gravitational force in Newtons of attraction. Given: Earth-moon
d = 3.84*10^8 m Earth/Moon M1 = 5.87*10^24 kg, M2 = 7.36*10^22 kg
r = d/2 = 1.92*10^8 m
F1 = G*m*M1/r^2
F2 = G*m*M2/r^2
F = F1 - F2
= G*m*(M1 - M2)/r^2
= 6.67*10^(-11)*31500*(587-7.36)*10^22/1.92^2*10^16
= 6.67*3.15*57.964/3.6864
= 330.36 N
the net gravitational force in Newtons of attraction. Given: Earth-moon
d = 3.84*10^8 m Earth/Moon M1 = 5.87*10^24 kg, M2 = 7.36*10^22 kg
r = d/2 = 1.92*10^8 m
F1 = G*m*M1/r^2
F2 = G*m*M2/r^2
F = F1 - F2
= G*m*(M1 - M2)/r^2
= 6.67*10^(-11)*31500*(587-7.36)*10^22/1.92^2*10^16
= 6.67*3.15*57.964/3.6864
= 330.36 N
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