What is the tangent line to y = 5x^2 – 6x + 3 at (0,3)?

👨🏻‍🏫 學術台數學

[匿名]

2015-09-16 11:35 pm

回答 (1)

Iggy Rocko

2015-09-16 11:38 pm

✔ 最佳答案

dy/dx = 10x - 6
dy/dx(at x = 0) = 10(0) - 6 = -6
Tangent line is
y - 3 = -6(x - 0)
y = -6x + 3

👍 0 👎 0