Find second derivative of 3xln(x). PLEASE show steps!?
回答 (2)
2015-09-15 2:00 am
f'(x) = 3[ln(x)+x/x] = 3ln(x) + 3
f"(x) = 3/x
f"(x) = 3/x
2015-09-15 1:57 am
d/dx(3xlnx) =
3lnx + 3x(1/x) =
3lnx + 3
d^2/dx^2(3xlnx) =
d/dx(3lnx + 3) =
3/x
3lnx + 3x(1/x) =
3lnx + 3
d^2/dx^2(3xlnx) =
d/dx(3lnx + 3) =
3/x
收錄日期: 2021-05-01 22:43:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150914175229AA90lVw