Find second derivative of 3xln(x). PLEASE show steps!?

2015-09-15 1:52 am

回答 (2)

2015-09-15 2:00 am
f'(x) = 3[ln(x)+x/x] = 3ln(x) + 3
f"(x) = 3/x
2015-09-15 1:57 am
d/dx(3xlnx) =
3lnx + 3x(1/x) =
3lnx + 3
d^2/dx^2(3xlnx) =
d/dx(3lnx + 3) =
3/x


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