請問8~11題的過程及答案，謝謝~~~?

8
(3+√8)^4
=(9+6√8+8)^2
=(17+6√8)^2
=289+204√8+288
=577+408√2
=1153.991
整數部分=1153
9
√{3+2√[5+12√(3+2√2)]}
=√{3+2√[5+12(√2+1)]}
=√[3+2√(17+12√2)]
=√[3+2√(17+2√72)]
=√[3+2(3+√8)]
=√(9+2√8)
=√8+1
a=3，b=√8-2
a+b+2=√8+3，b－1=√8－3
1/(a+b+2)－1/(b－1)
=(3－√8)/(9－8)+(3+√8)/(9－8)
=6

10
√(17+√288)
=√(17+2√72)
=3+√8
a=5，b=√8－2
b+2=√8
b^2+4b+4=8
b^2+4b=4
So
√[b+2+√(b^2+4b)]/√[b+2－√(b^2+4b)]
=√(√8+2)/√(√8－2)
=√[(√8+2)^2/4]
=(√8+2)/2
=√2+1

11
設a為正整數，若√3介於(a+5)/a與(a+6)/(a+1)之間，則a之值為?
Sol
[(a+5)/a]/[(a+6)/(a+1)
=(a+5)(a+1)/[a(a+1)
=(a^2+6a+5)/(a^2+6a)>1
(a+5)/a>(a+6)/(a+1)
(a+6)/(a+1)<√3<(a+5)/a
(a+6)/(a+1)<√3
a+6<√3(a+1)
a+6<√3a+√3
6－√3<(√3－1)a
(6－√3)/(√3－1)<a
(6－√3)(√3+1)/2<a
(6√3+6－3－√3)/2<a
(5√3+3)/2<a
5.82<a
√3<(a+5)/a
√3a<a+5
(√3－1)a<5
a<5/(√3－1)
a<5(√3+1)/2
a<6.84
5.83<a<6.83
a=6