8 different flags are hoisted in random order. Let F be the event that any 2 of 3 particular flags are not next to each other. Find P(F)?

[匿名]

2015-09-13 2:26 pm

Maths probability

更新1:

Pls add explaination

回答 (1)

匿名人

2015-09-14 6:03 am

F = 5! x ₆P₃ = 14400
Therefore,
P(F) = 14400 / 8! = 5/14

👍 2 👎 0

收錄日期: 2021-04-18 00:14:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150913062606AA7nF1g

檢視 Wayback Machine 備份