11將邊長為12的正方形ABCD與 https://www.flickr.com/photos/101292575@N06/21137715738/in/dateposted-public/?
回答 (2)
2015-09-12 5:50 pm
4*12+30
正方形周長+三角形周長
=(AB+BC+CP+PD+DH+HA)+(EH+HF+FP+PG+GE)
=(AB+BC+CP+PG+GE+EH+HA)+(PD+DH++HF+FP)
=(AB+BC+CP+PG+GE+EH+HA)+(PD+DH++HF+FP)
=64+四邊形DHFP周長
四邊形DHFP周長=14
正方形周長+三角形周長
=(AB+BC+CP+PD+DH+HA)+(EH+HF+FP+PG+GE)
=(AB+BC+CP+PG+GE+EH+HA)+(PD+DH++HF+FP)
=(AB+BC+CP+PG+GE+EH+HA)+(PD+DH++HF+FP)
=64+四邊形DHFP周長
四邊形DHFP周長=14
收錄日期: 2021-04-30 20:00:13
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150912053240AAgqC38