rationalise the denominator and simplyfy (( root (3) + root(2) / root(3) - root(2) )) + (( root(3) - root(2) / root(3) + root(2) ))?
回答 (3)
2015-09-12 10:29 am
Assuming that meant to read as :-
[ √3 + √2 ] / [ √3 - √2 ] + [ √3 - √2 ] / [ √3 + √2 ]
[ √3 + √2 ] [ √3 + √2 ] + [ √3 - √2 ] [ √3 - √2 ]
--------------------------------------------------------------
[ √3 - √2 ] [ √3 + √2 ]
5 + 2√ 6 + 5 - 2 √6
10
[ √3 + √2 ] / [ √3 - √2 ] + [ √3 - √2 ] / [ √3 + √2 ]
[ √3 + √2 ] [ √3 + √2 ] + [ √3 - √2 ] [ √3 - √2 ]
--------------------------------------------------------------
[ √3 - √2 ] [ √3 + √2 ]
5 + 2√ 6 + 5 - 2 √6
10
2015-09-12 7:38 am
you have [ √3 + √2 ]² +[ √3 - √2 ]² = 3 + 2 + 2√6 - { 3 + 2 - 2 √6] = 4√6
2015-09-12 7:40 am
收錄日期: 2021-04-21 14:14:00
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150911233558AA4eolF