N2(g) + 3H2(g) --- 2NH3(g)
Calculate the number of moles of hydrogen required to react with 0.0935 mole of nitrogen, and the number of moles of ammonia that will form.
Calculate the number of moles?
2015-09-10 5:42 pm
回答 (3)
2015-09-10 5:43 pm
✔ 最佳答案
0.28 moles H20.187 moles NH3
2015-09-10 6:03 pm
N₂(g) + 3H₂(g) → 2NH₃(g)
Mole ratio N₂ : H₂ : NH₃ = 1 : 3 : 2
Molar mass of N₂ = 14.01 × 2 = 28.01 g/mol
No. of moles of N2 = (0.0935 g)/(28.01 g/mol) = 0.0935/28.01 mol
No. of moles of H2 required = (0.0935/28.01 mol) × 3 = 0.0100 mol ..... (Ans)
No. of moles of NH₃ formed = (0.0935/28.01 mol) × 2 = 0.00676 mol ..... (Ans)
Mole ratio N₂ : H₂ : NH₃ = 1 : 3 : 2
Molar mass of N₂ = 14.01 × 2 = 28.01 g/mol
No. of moles of N2 = (0.0935 g)/(28.01 g/mol) = 0.0935/28.01 mol
No. of moles of H2 required = (0.0935/28.01 mol) × 3 = 0.0100 mol ..... (Ans)
No. of moles of NH₃ formed = (0.0935/28.01 mol) × 2 = 0.00676 mol ..... (Ans)
2015-09-10 5:49 pm
...
. . N2 + . . 3H2 →. . 2NH3
0.0935. . .0.281. . . 0.187
. . . |_1 to 3_| . . . . . . . |
. . . |______1 to 2____|
When you get a good response,
please consider giving a best answer.
This is the only reward we get.
. . N2 + . . 3H2 →. . 2NH3
0.0935. . .0.281. . . 0.187
. . . |_1 to 3_| . . . . . . . |
. . . |______1 to 2____|
When you get a good response,
please consider giving a best answer.
This is the only reward we get.
收錄日期: 2021-04-18 00:18:46
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