某等比數列的公比是-5/2,第n項是625,首n項之和是451,求n的值。?
回答 (1)
首項 = a
公比 r = -5/2
T(n) = 625
a r^(n - 1) = 625
a r^(n - 1) × r = 625 × r
a r^n = 625 × (-5/2)
a (-5/2)^n = -3125/2 ...... [1]
S(n) = 451
a (1 - r^n) / [1 - r] = 415
a (1 - r^n) / [1 - (-5/2)] = 415
a (1 - r^n) = 451 × (7/2)
a - a (-5/2)^n = 3157/2 ...... [2]
[1] + [2] :
a = 16
代入 [1] 中:
16 × (-5/2)^n = -3125/2
(-5/2)^n = -3125/32
(-5/2)^n = (-5/2)^5
n = 5 ...... (答案)
收錄日期: 2021-04-18 00:17:28
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