36 and 42 algebra help?
回答 (3)
2015-09-09 1:02 pm
36).
-3(4x - 1)^(1/5) + 2 = 8
-3(4x - 1)^(1/5) = 6
(4x - 1)^(1/5) = -2
(4x - 1) = (-2)^5
4x = -31
x = -31/4
42).
√(k - 2) = √(2k + 3) - 2
√(2k + 3) - √(k - 2) = 2
(2k + 3 + k - 2) - √(2k + 3)√(k - 2) = 4
3k - √(2k + 3)√(k - 2) = 3
Complex solutions:
k ≈ 1.2143 - 0.8175 i
k ≈ 1.2143 + 0.8175 i
-3(4x - 1)^(1/5) + 2 = 8
-3(4x - 1)^(1/5) = 6
(4x - 1)^(1/5) = -2
(4x - 1) = (-2)^5
4x = -31
x = -31/4
42).
√(k - 2) = √(2k + 3) - 2
√(2k + 3) - √(k - 2) = 2
(2k + 3 + k - 2) - √(2k + 3)√(k - 2) = 4
3k - √(2k + 3)√(k - 2) = 3
Complex solutions:
k ≈ 1.2143 - 0.8175 i
k ≈ 1.2143 + 0.8175 i
2015-09-09 11:39 am
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2015-09-09 11:23 am
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