Balance the following chemical equation, then answer the following question.
C8H18(g) + O2(g) →CO2(g)+H2O(g)
How many grams of oxygen are required to react with 10.0 grams of octane (C8H18) in the combustion of octane in gasoline?
Chemistry Homework?
2015-09-08 2:26 am
回答 (1)
2015-09-08 5:57 am
2 C8H18(g) + 25 O2(g) → 16 CO2(g) + 18 H2O(g)
(10.0 g C8H18) / (114.2285 g C8H18/mol) x (25 mol O2 / 2 mol C8H18) x (31.99886 g O2/mol) = 35.0 g O2
(10.0 g C8H18) / (114.2285 g C8H18/mol) x (25 mol O2 / 2 mol C8H18) x (31.99886 g O2/mol) = 35.0 g O2
收錄日期: 2021-04-21 14:01:31
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