IF 4x+(3x-y)i=3-6i find x and y complex numbers?
回答 (3)
2015-09-07 2:50 pm
4x + (3x-y)i = 3 - 6i
(3x - y + 6) i + 4x - 3 = 0
This implies
3x - y + 6 = 0 ........(1)
and
4x - 3 = 0...........(2)
From (2)
x = 3/4
Putting this in (1)
y = 33/4
(3x - y + 6) i + 4x - 3 = 0
This implies
3x - y + 6 = 0 ........(1)
and
4x - 3 = 0...........(2)
From (2)
x = 3/4
Putting this in (1)
y = 33/4
2015-09-07 3:59 pm
4x = 3
x = 3/4
9/4 - y = - 6
33/4 = y
x = 3/4 , y = 33/4
x = 3/4
9/4 - y = - 6
33/4 = y
x = 3/4 , y = 33/4
2015-09-07 2:56 pm
4x=3
3x-y = -6
and solve
3x-y = -6
and solve
收錄日期: 2021-04-21 14:00:32
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150907063508AAnqmuu