求解答 唔該!!!!!!?

2015-09-06 7:36 pm

回答 (2)

2015-09-07 1:01 am
15
(a)
-1<=Sinx<=1
-4<=4Sinx<=4
-4<=-4Sinx<=4
3-4<=3-4Sinx<=3-4
-1<=3-4Sinx<=7
(b)
-1<=Cosx<=1
-1<=-Cosx<=1
0<=1-Cosx<=2
2^0<=2^(1-Cosx)<=2^2
1/4<=1/2^(1-Cosx)<=1
16
p=Tanx
Cos2x=(p^2-1)/(p^2+1),Sin2x=2p(p^2+1)
5Cos^2 x+SinxCosx=2
10Cos^2 x+2SinxCosx=4
5(1+Cos2x)+Sin2x=4
5+5Cos2x+Sin2x=4
5+5(p^2-1)/(p^2+1)+2p/(p^2+1)=4
5(p^2-1)/(p^2+1)+2p/(p^2+1)+1=0
5(p^2-1)+2p+(p^2+1)=0
6p^2+2p-4=0
3p^2+p-2=0
(3p-2)(p+1)=0
p=2/3 or p=-1
17
8Cos^2 x-2Sinx-5=0
8-8Sin^2 x-2Sinx-5=0
8Sin^2 x+2Sinx-3=0
(4Sinx+3)(2Sinx-1)=0
Sinx=-3/4 or Sinx=1/2
x=311.41度 or x=228.59度 or x=30度 or x=150度
18
(a)
y=3(2x+1)^2+4
(2x+1)^2>=0
3(2x+1)^2>=0
3(2x+1)^2+4>=4
y>=4
(b)
y=x^2+6x+2
=(x^2+6x+9)-7
=(x+3)^2-7
(x+3)^2>=0
(x^2+3)^2-7>=-7
y>=-7
19
y=2-x,x^2-y^2=8
x^2-(2-x)^2=8
x^2-(x^2-4x+4)=8
4x-4=8
x=3
y=-1
2015-09-06 10:25 pm
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