Find k if 2x +(3k 1)x 8 has equal roots?
回答 (1)
2015-09-07 3:55 am
題目不全
若是2x^2+(3k+1)x+8=0
D=b^2-4ac=(3k+1)^2-4*2*8=0
==>(3k-7)(k+3)=0
==>k=7/3或k=-3
若是2x^2+(3k+1)x+8=0
D=b^2-4ac=(3k+1)^2-4*2*8=0
==>(3k-7)(k+3)=0
==>k=7/3或k=-3
收錄日期: 2021-05-03 15:17:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150906092336AAwMfm9