✔ 最佳答案
Suppose the range you mean is 0 ≦ x < 2π
sin 4x + sin 2x = cos x
2 * sin (4x+2x)/2 * cos (4x-2x)/2 = cosx
2 * sin 3x * cos x = cos x
cos x ( 1 - 2 sin 3x ) = 0
cos x = 0 or sin 3x = 1/2
cos x = 0
x = π/2 or 3π/2
sin 3x = 1/2 and 0 ≦ 3x < 6π
3x = π/6 , 5π/6 , 13π/6 , 17π/6 , 25π/6 , 29π/6
x = π/18 , 5π/18 , 13π/18 , 17π/18 , 25π/18 , 29π/18
Ans: x = π/2 , 3π/2 , π/18 , 5π/18 , 13π/18 , 17π/18 , 25π/18 , 29π/18