高二數學,化簡sin平方(20度+θ)+sin平方(70度-θ)+cos平方(40度+θ+cos平方(50度-θ)?

2015-09-06 6:10 am

回答 (2)

2015-09-06 6:20 am
✔ 最佳答案
Sin^2 (20度+θ)+Sin^2 (70度-θ)+Cos^2 (40度+θ)+Cos^2 (50度-θ)
=Sin^2 (20度+θ)+Cos^2 (20度+θ)+Cos^2 (40度+θ)+Sin^2 (50度-θ)
=1+1
=2
2015-11-22 1:37 am
sin^2 (20度+θ)+sin^2 (70度-θ)+cos^2 (40度+θ)+cos^2 (50度-θ)
=sin^2 (20+θ)+cos^2 [90-(70度-θ)]+cos^2 (40度+θ)+sin^2 [90-(50度-θ)]
=sin^2 (20+θ)+cos^2 (20+θ)+cos^2 (40度+θ)+sin^2 (40度+θ)
=1+1
=2


收錄日期: 2021-04-18 00:10:38
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150905221058AAtAjpI

檢視 Wayback Machine 備份