PLEASE HELP. Ive looked all over for answers on how to even attempt to solve this problem.
****please note that the answers have to be an exact number. I can not put infinity symbols!!!***
Determining the infinite limit.
lim
x→−9(negative sign raised)
of x+8/x+9
a) As x approaches −9 from the left, the numerator approaches ____
b) Also, as x approaches −9 from the left, the denominator approaches ____ from the negative side
Calculus Question On Infinite Limits?
2015-09-05 11:29 pm
回答 (2)
2015-09-05 11:45 pm
(x + 8) / (x + 9) =>
(x + 9 - 1) / (x + 9) =>
(x + 9) / (x + 9) - 1 / (x + 9) =>
1 - 1/(x + 9)
1/(x + 9) is just 1/x shifted over to the left by 9 units, so we're really looking at the limit of 1/x as x approaches 0
x goes to 0 for 1/x
As x approaches from the left, 1/x goes to negative infinity
As x approaches from the right, 1/x goes to positive infinity
(x + 8) / (x + 9)
x + 8 is the numerator
as x approaches -9 from the left, x + 8 approaches -1
x + 9 is the denominator
as x approaches -9 from the left, x + 9 approaches 0
(x + 9 - 1) / (x + 9) =>
(x + 9) / (x + 9) - 1 / (x + 9) =>
1 - 1/(x + 9)
1/(x + 9) is just 1/x shifted over to the left by 9 units, so we're really looking at the limit of 1/x as x approaches 0
x goes to 0 for 1/x
As x approaches from the left, 1/x goes to negative infinity
As x approaches from the right, 1/x goes to positive infinity
(x + 8) / (x + 9)
x + 8 is the numerator
as x approaches -9 from the left, x + 8 approaches -1
x + 9 is the denominator
as x approaches -9 from the left, x + 9 approaches 0
2015-09-05 11:43 pm
a) the numerator approaches -1
b) the denominator approaches 0
b) the denominator approaches 0
收錄日期: 2021-05-01 15:26:13
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