A sprung gun at ground level fires a tennis ball at an angle of 58°. The ball lands 11 m away. What was the ballʹs initial speed? using cal?

👨🏻‍🏫 學術台物理學

[匿名]

2015-09-05 12:00 am

回答 (1)

Steve

2015-09-05 3:03 am

R = V²*sin(2Θ)/g → V = √[R*g/sin(2Θ)] = 10.95 m/s

參考: Std trajectory eq

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