Chemistry Question help please?

(142 km) x (0.6214 mi/km) / (30.0 mi/gal) x (3.78 L/gal) = 11.1 L

(7 days) x (111 km/day) x (0.6214 mi/km) / (32.0 mi/gal) x (3.78 L/gal) x (1.10 euros/L) x ($1.26/euro) = $79.05

In Europe, gasoline efficiency is measured in km/L. If your car's gas mileage is 30.0 mi/gal , how many liters of gasoline would you need to buy to complete a 142-km trip in Europe? Use the following conversions: 1km=0.6214mi and 1gal=3.78L.

142 km
= 142 × 0.6214 mi

Volume of gasoline
= (142 × 0.6214 mi) / (30 mi/gal)
= (142 × 0.6214 / 30 gal) × (3.78 L/gal)
= 11.1 L


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While in Europe, if you drive 111 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per liter and your car's gas mileage is 32.0 mi/gal ? Assume that 1euro=1.26dollars.

111 km
= 111 × 0.6214 mi

Volume of gasoline per day
= (111 × 0.6214 mi) / (32 mi/gal)
= (111 × 0.6214 / 32 gal) × (3.78 L/gal)
= 111 × 0.6214 × 3.78 / 32 L

Amount spent in one week
= (111 × 0.6214 × 3.78 / 32 L) × 7 × (1.1 euros/L) × (1.26 dollars/euro)
= 79.0 dollars