P= nRT/V , find V when P=0.97, n= 0.0363, R=0.0821 T=304?

👨🏻‍🏫 學術台數學

[匿名]

2015-09-04 8:42 am

回答 (4)

賣女孩的火柴

2015-09-04 8:53 am

P = n R T / V
Thus, V = n R T / P

V = (0.0363 mol) × [0.0821 atm L/(K mol)] × (304 K) / (0.97 atm) = 0.934 L

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[匿名]

2015-09-04 8:44 am

.934 Liters

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[匿名]

2015-09-04 9:29 am

P = nRT/ V , so V = n RT/P , where P = 0.97 , n = 0.0363 , R = 0.0821 and T = 304 , so V = 0.0363 X 0.0821X 304/ 0.97 = 0.934010226

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Como

2015-09-04 9:14 am

V = n R T / P

V = 0.0363 x 0.0821 x 304 / 0.97

V = 0.0934

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