x+y=z
1+2=3
3+3=6
6+4=10
10+5=15
15+6=21
更新1:
I need to find an equation that will allow me to enter X and solve for Y, or vice versa
Algorithm to a problem, please help?
回答 (1)
2015-09-03 7:08 pm
f(n) = f(n - 1) + n ; where f(1) = 1
This is a recursive function, a function that calls itself until it meets the exit condition. So if we start with solving for f(6) and want to find its value (which you state above is 21), it would look like this:
f(n) = f(n - 1) + n
f(6) = f(6 - 1) + 6
f(6) = f(5) + 6
f(6) = f(5 - 1) + 5 + 6
f(6) = f(4) + 11
f(6) = f(4 - 1) + 4 + 11
f(6) = f(3) + 15
f(6) = f(3 - 1) + 3 + 15
f(6) = f(2) + 18
f(6) = f(2 - 1) + 2 + 18
f(6) = f(1) + 20
f(6) = 1 + 20
f(6) = 21
And I get the same thing that you get
This is a recursive function, a function that calls itself until it meets the exit condition. So if we start with solving for f(6) and want to find its value (which you state above is 21), it would look like this:
f(n) = f(n - 1) + n
f(6) = f(6 - 1) + 6
f(6) = f(5) + 6
f(6) = f(5 - 1) + 5 + 6
f(6) = f(4) + 11
f(6) = f(4 - 1) + 4 + 11
f(6) = f(3) + 15
f(6) = f(3 - 1) + 3 + 15
f(6) = f(2) + 18
f(6) = f(2 - 1) + 2 + 18
f(6) = f(1) + 20
f(6) = 1 + 20
f(6) = 21
And I get the same thing that you get
收錄日期: 2021-04-21 13:55:32
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https://hk.answers.yahoo.com/question/index?qid=20150903110447AAMMeUH