What is the molar mass of manganese(II) nitrate tetrahydrate Mn(NO3)2·4H2O)?
回答 (3)
2015-09-01 9:07 pm
Method 1 : by calculation
Relative atomic mass :
Mn = 54.94, N = 14.01, O = 16.00, H = 1.01
Molar mass of Mn(NO₃)₂•4H₂O
= 54.94 + 14.01×2 + 16.00×10 + 1.01×8
= 251.04 g/mol
====
Method 2 : by searching in web
For example, according to the following web-page :
http://www.endmemo.com/chem/compound/mnno3_24h2o.php
Molar mass of Mn(NO₃)₂•4H₂O = 251.009 (g/mol)
Relative atomic mass :
Mn = 54.94, N = 14.01, O = 16.00, H = 1.01
Molar mass of Mn(NO₃)₂•4H₂O
= 54.94 + 14.01×2 + 16.00×10 + 1.01×8
= 251.04 g/mol
====
Method 2 : by searching in web
For example, according to the following web-page :
http://www.endmemo.com/chem/compound/mnno3_24h2o.php
Molar mass of Mn(NO₃)₂•4H₂O = 251.009 (g/mol)
2015-09-01 9:04 pm
You simply add up the molar masses of all of the atoms in the compound.
Mn + 2 N + 6 O + 8 H + 4 O
54.94 + 2(14.01) + 6(16.00) + 8(1.01) + 4(16.00) = 251.04 g/mol
Mn + 2 N + 6 O + 8 H + 4 O
54.94 + 2(14.01) + 6(16.00) + 8(1.01) + 4(16.00) = 251.04 g/mol
收錄日期: 2021-04-20 15:58:38
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150901124259AAjiEtx