find the variance of first five prime numbers?
回答 (2)
2015-08-31 12:50 pm
2015-08-31 2:00 pm
2,3,5,7,11 are the first five prime numbers
Σx = 2+3+5+7+11= 28
Σx^2 = 2^2 + 3^2 + 5^2 + 7^2 + 11^2 = 208
n= 5 (number of observations)
Variance = (∑x^2 - ( ∑ x)^2 / n ) / (n-1)
= ( 208 - (28)^2 / 5 ) / 4
= 12.8
Σx = 2+3+5+7+11= 28
Σx^2 = 2^2 + 3^2 + 5^2 + 7^2 + 11^2 = 208
n= 5 (number of observations)
Variance = (∑x^2 - ( ∑ x)^2 / n ) / (n-1)
= ( 208 - (28)^2 / 5 ) / 4
= 12.8
收錄日期: 2021-04-21 13:52:09
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