How to write equation?
2015-08-31 5:10 am
How do you write and equation in slope-intercept form that passes through (4,6) and intersects the y-axis at 17?
回答 (4)
2015-08-31 5:24 am
How do you write and equation in slope-intercept form that passes through (4,6) and intersects the y-axis at 17?
y = mx + b <===slope-intercept form.
Substitute:
b= y-intercept= 17
x=4
y=6
y = mx + b <===solve for m.
6= m(4) +17
m= (6 -17)/4
m= -11/4
So, the equation of the line is:
y= -11/4x + 17 <===Answer(slope-intercept form.)
y = mx + b <===slope-intercept form.
Substitute:
b= y-intercept= 17
x=4
y=6
y = mx + b <===solve for m.
6= m(4) +17
m= (6 -17)/4
m= -11/4
So, the equation of the line is:
y= -11/4x + 17 <===Answer(slope-intercept form.)
2015-08-31 5:15 am
The line passes through (4, 6) and (0, 17).
Slope, m = (17 - 6)/(0 - 4) = -11/4
y-intercept, c = 17
The slope-intercept form: y = mx + c
Thus the required equation is: y = -(11/4)x + 17
Slope, m = (17 - 6)/(0 - 4) = -11/4
y-intercept, c = 17
The slope-intercept form: y = mx + c
Thus the required equation is: y = -(11/4)x + 17
2015-08-31 5:18 am
rise = 6-17 = -11
run = 4-0 = 4
slope = rise/run = -11/4
y = (-11/4)x + 17
run = 4-0 = 4
slope = rise/run = -11/4
y = (-11/4)x + 17
2015-08-31 10:01 am
m = [ 6 - 17 ] / [ 4 - 0 [ = - 11/4
y - 6 = (-11/4) x
y = (-11/4) x + 6
y - 6 = (-11/4) x
y = (-11/4) x + 6
收錄日期: 2021-04-18 00:10:56
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