1a. Simplify http://i.imgur.com/6iAByek.jpg
b. Hence, simplify http://i.imgur.com/E913bjl.jpg
c. Using the result of (b), or otherwise, simplify the following expression: http://i.imgur.com/QrzQxoS.jpg
---F.2 Math?
2015-08-31 3:58 am
回答 (1)
2015-08-31 6:06 am
1.
=√(n+1)*√(n+1)－√n*√n]
=(n+1)－n
=1
2.
=[√(n+1)－√n]/｛[√(n+1)－√n]*[√(n+1)+√n]｝
=[√(n+1)－√n]/[(n+1)－n]
=√(n+1)－√n
3
=(√2025－√2024)+(√2024－√2023)+√2023－√2022)+…+(√4－√3)+(√3－√2)+(√2－√1)
=√2025－√1
=45－1
=44
=√(n+1)*√(n+1)－√n*√n]
=(n+1)－n
=1
2.
=[√(n+1)－√n]/｛[√(n+1)－√n]*[√(n+1)+√n]｝
=[√(n+1)－√n]/[(n+1)－n]
=√(n+1)－√n
3
=(√2025－√2024)+(√2024－√2023)+√2023－√2022)+…+(√4－√3)+(√3－√2)+(√2－√1)
=√2025－√1
=45－1
=44
收錄日期: 2021-04-30 19:58:12
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150830195808AA3td7l