Evaluate sin 7x ln(sin 7x) dx.
Hint: Use Integration by Parts as a first step.
I have the answer as:
1/7 (ln|sin(7x/2)|-ln|cos(7x/2)|-cos(7x)(ln|sin(7x)-1))+C
But I need help understanding the steps/process
Evaluate sin 7x ln(sin 7x) dx?
2015-08-31 3:49 am
回答 (2)
2015-08-31 3:56 am
u = ln (sin 7x ) ; dv = sin 7x dx
du = 7cot 7x ; v = - cos 7x / 7.....v du = - cos² 7x / sin 7x = sin 7x - csc 7x..integrate this
du = 7cot 7x ; v = - cos 7x / 7.....v du = - cos² 7x / sin 7x = sin 7x - csc 7x..integrate this
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