Find two numbers whose sum is 6 and product is 14?

x+y = 6
y = 6-x

xy = 14
x(6-x) = 14
6x - x² = 14
x² - 6x + 14 = 0

quadratic formula
x = [6 ± √(6² – 4·1·14)] / [2·1]
 = [6 ± √(-20)] / 2
 = [6 ± (2√5)i] / 2
 = 3 ± (√5)i

x = 3 + √5i
y = 3 - √5i

x + y = 6
xy = 14
x(6 - x) = 14
x^2 - 6x + 14 = 0
Complex solutions:
x = 3 - 2.2361 i
x = 3 + 2.2361 i

No whole numbers for this.

you have x y = 14 and x + y = 6---> y = 6 - x ---> 6 x - x² = 14---> x² - 6x + 14 = 0----> x = 3 ± i √5...thus no real number exists for an answer