4(-2)² + 8(-2) + 3(-2) + 6 =?
回答 (4)
4(-2)² + 8(-2) + 3(-2) + 6
= 4×4 - 8×2 - 3×2 + 6
= 16 - 16 - 6 + 6
= 0
4(-2)² + 8(-2) + 3(-2) + 6 =
(-2) (4(-2) + 8 + 3) + 6 =
(-2) (-8 + 8 + 3) + 6 =
(-2) (3) + 6 =
-6 + 6 =
0
-2 squared = 4
4 times 4 = 16
8 times -2 = -16
So those two cancel each other.
3 times -2 = -6
+ 6 =0
Your Answer is ZERO
收錄日期: 2021-04-18 00:07:21
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