If you have 80.5 g of carbon that can be converted to acetylene, what mass of hydrogen will be needed for the conversion?
回答 (4)
2015-08-30 9:39 pm
2C(g) + H₂ (g) → CH≡CH(g)
No. of moles of C = 80.5/12 mol
No. of moles of H₂ needed = (80.5/12) × (1/2) = 80.5/24 mol
Mass of H₂ needed = (80.5/24) × 2 = 6.71 g
No. of moles of C = 80.5/12 mol
No. of moles of H₂ needed = (80.5/12) × (1/2) = 80.5/24 mol
Mass of H₂ needed = (80.5/24) × 2 = 6.71 g
2015-08-30 9:34 pm
2 C + H2 → C2H2
(80.5 g C) / (12.01078 g C/mol) x (1 mol H2 / 2 mol C) x (2.01588 g H2/mol) = 6.76 g H2
(80.5 g C) / (12.01078 g C/mol) x (1 mol H2 / 2 mol C) x (2.01588 g H2/mol) = 6.76 g H2
2015-08-30 9:24 pm
C + H2 -----> CH2
1 mole of H2 is required per mole C
moles C: 80.5 g/12 g/mole C= 6.7, therefore 6.7 moles H2 required
6.7 moles H2 x 2 g/mole H2= 13.4 g H2
1 mole of H2 is required per mole C
moles C: 80.5 g/12 g/mole C= 6.7, therefore 6.7 moles H2 required
6.7 moles H2 x 2 g/mole H2= 13.4 g H2
2015-08-30 9:27 pm
They are saying it is wrong. This is the original statement. Acetylene, used for welding, contains 24.02 g of carbon for every 2.02 g of hydrogen.
收錄日期: 2021-04-18 00:09:15
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