how to solve 6X^2 -6x +13 = 0 using quadratic formula?

ax^2+bx+c is a quadratic

The quadratic formula is:

x=[-b±√(b^2-4ac)]/(2a)

x = [ - b ± √ (b² - 4ac) ] / (2a)
x = [ 6 ± √ (36 - 312) ] / 12
x = [ 6 ± √ (276) ] / 12
x = [ 6 ± 2√69 ] / 12
x = [ 3 ± √69 ] / 6

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