how to solve 6X^2 -6x +13 = 0 using quadratic formula?
回答 (3)
2015-08-30 6:09 pm
ax^2+bx+c is a quadratic
The quadratic formula is:
x=[-b±√(b^2-4ac)]/(2a)
The quadratic formula is:
x=[-b±√(b^2-4ac)]/(2a)
2015-08-30 7:02 pm
x = [ - b ± √ (b² - 4ac) ] / (2a)
x = [ 6 ± √ (36 - 312) ] / 12
x = [ 6 ± √ (276) ] / 12
x = [ 6 ± 2√69 ] / 12
x = [ 3 ± √69 ] / 6
x = [ 6 ± √ (36 - 312) ] / 12
x = [ 6 ± √ (276) ] / 12
x = [ 6 ± 2√69 ] / 12
x = [ 3 ± √69 ] / 6
收錄日期: 2021-04-18 00:08:22
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https://hk.answers.yahoo.com/question/index?qid=20150830100447AAqZggf