Solve the linear equation (2x-3)/4=[(x-4)/2] - [(x+1)/4]?
2015-08-30 5:58 pm
I keep getting -4 but that isn't correct because it doesn't check. Does that mean it has no solutions? If I'm wrong how do you do this step-by-step? Thanks <3
回答 (4)
2015-08-30 6:06 pm
Make sure they all have the same denominator of 4...
(2x-3)/4=(2x-8-x-1)/4
2x-3=x-9
x-3=-9
x=-6
...
(2(-6)-3)/4=(-6-4)/2-(-6+1)/4
-15/4=-10/2-(-5/4)
-15/4=-10/2+5/4
-15/4=-20/4+5/4
-15/4=-15/4
(2x-3)/4=(2x-8-x-1)/4
2x-3=x-9
x-3=-9
x=-6
...
(2(-6)-3)/4=(-6-4)/2-(-6+1)/4
-15/4=-10/2-(-5/4)
-15/4=-10/2+5/4
-15/4=-20/4+5/4
-15/4=-15/4
2015-08-30 6:02 pm
(2x - 3)/4 = [(x - 4)/2] - [(x + 1)/4]
(2x - 3)/4 = [(2x - 8)/4] - [(x + 1)/4]
2x - 3 = (2x - 8) - (x + 1)
2x - 3 = 2x - 8 - x - 1
2x - 3 = x - 9
x = -6
(2x - 3)/4 = [(2x - 8)/4] - [(x + 1)/4]
2x - 3 = (2x - 8) - (x + 1)
2x - 3 = 2x - 8 - x - 1
2x - 3 = x - 9
x = -6
2015-10-16 3:57 am
First, multiply through by 4 getting 2x-3=2x-8-x-1,
ie., -3=-8-x-1, ie., 3=x+9, ie., x = - 6.
ie., -3=-8-x-1, ie., 3=x+9, ie., x = - 6.
2015-08-30 6:23 pm
2x - 3 = 2x - 8 - x - 1
x = - 6
x = - 6
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