Trigo Question?
回答 (2)
2015-08-30 7:45 am
6. (c)
Draw DH perpendicular to AB produce, and DH cuts AB produce at H.
DH (the perpendicular distance from the light house to the path of the ship) is the shortest distance between the ship and the light houe.
As found in (a), AD = 5.2 sin115° / sin30° km = 9.4 km
In ΔADH :
sinA = DH / AD
sin35° = DH / (5.2 sin115° / sin30° km)
DH = 5.2 sin115° sin35° / sin30° km
DH = 5.4 km
OR:
In ΔADH :
sinA = DH / AD
sin35° = DH / (9.4 km)
DH = 9.4 sin35° km
DH = 5.4 km
Draw DH perpendicular to AB produce, and DH cuts AB produce at H.
DH (the perpendicular distance from the light house to the path of the ship) is the shortest distance between the ship and the light houe.
As found in (a), AD = 5.2 sin115° / sin30° km = 9.4 km
In ΔADH :
sinA = DH / AD
sin35° = DH / (5.2 sin115° / sin30° km)
DH = 5.2 sin115° sin35° / sin30° km
DH = 5.4 km
OR:
In ΔADH :
sinA = DH / AD
sin35° = DH / (9.4 km)
DH = 9.4 sin35° km
DH = 5.4 km
2015-08-30 2:24 am
the shortest distance ≈ 5.4378
收錄日期: 2021-04-11 21:11:14
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https://hk.answers.yahoo.com/question/index?qid=20150829085953AAWHwKO