Given that f(x) = 3x - 7 and g(x) = x² - 4, what is the value of f(g(f(3)))?

f (3) = 2

f [ g (2) ] = f [ 0 ] = - 7

f(3)
= 3(3) ‒ 7
= 2

g(f(3))
= g(2)
= (2)² ‒ 4
= 0

f(g(f(3)))
= f(0)
= 3(0) ‒ 7
= ‒7

f(3) = 2
g(2) = 0
f(0) = -7
f(g(f(3))) = -7

f(3) is 3*3 - 7. Do that calculation. Get the number. Call it a.

g(f(3)) is a^2 - 4. Do that calculation. Call it b.

f(g(f(3)) is 3*b - 7.

8

f(3) = 3
g(3^2-4) = 5
f((3*5)-7) = 8