✔ 最佳答案
前一個問題的回答用在這裡仍是可行的, 例如
f(x) = [27*(x/27-[x/27])]
則
f(0) = 0, f(1) = 1, f(2) = 2, . . . . f(26) = 26,
f(27) = 0, f(28) = 1, f(29) = 2, ... , f(52) = 26,
{0,1,...,26} 的任一排列函數與上列 f(x) 搭配可得
不同形狀的週期及數.
同樣, 可做出不同週期的週期函數, 例如
g(x) = [27*(x/54-[x/54])]
也可與其他非負整數值函數合成, 構造出非週期函數,
例如 h(x) = [27*(x^2/27-[x^2/27])]
則
h(0) = 0, h(1) = 1, h(2) = 4, h(3) = 9, h(4) = 16, h(5) = 25,
h(6) = 9, h(7) = 22, h(8) = 10, . . .