求procedure+answer
p^4+4p^3q+4p^2q^2-q^4
16a^2-48a+36-9b^2-12b-4
普通因式分解問題
2015-07-22 7:52 pm
回答 (2)
2015-07-22 8:33 pm
✔ 最佳答案
p⁴＋4p³q＋4p²q²－q⁴＝(p²＋2pq)²－(q²)²＝(p²＋2pq＋q²)(p²＋2pq－q²)＝(p＋q)²(p²＋2pq－q²)
16a²－48a＋36－9b²－12b－4＝(16a²－48a＋36)－(9b²＋12b＋4)
＝(4a＋6)²－(3b＋2)²
＝(4a＋3b＋8)(4a－3b＋4)
2015-07-22 18:31:23 補充：
Thanks for your correction, I am wrong.
2015-07-22 10:00 pm
16a²－48a＋36－9b²－12b－4
＝(16a²－48a＋36)－(9b²＋12b＋4)
＝(4a－6)²－(3b＋2)² <--- (4a＋6)² is not right, '+' should be "－"
＝(4a＋3b－8)(4a－3b－4)
After completion, the first and last terms can be checked for correctness.
The last constant term = －8 x －4 = ＋32 = ＋36 － 4
＝(16a²－48a＋36)－(9b²＋12b＋4)
＝(4a－6)²－(3b＋2)² <--- (4a＋6)² is not right, '+' should be "－"
＝(4a＋3b－8)(4a－3b－4)
After completion, the first and last terms can be checked for correctness.
The last constant term = －8 x －4 = ＋32 = ＋36 － 4
收錄日期: 2021-04-11 21:10:26
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150722000051KK00029