更新1:
please show steps so that I can know how to work it! :)
Use the four step process to find f'(x) for the function f(x) = 2/x^2?
回答 (3)
2015-07-19 12:13 am
f(x) = 2/x^2 = 2x^-2
f'(x) = 2(-2)x^(-2-1)
= -4x^-3
= -4/x^3
f'(x) = 2(-2)x^(-2-1)
= -4x^-3
= -4/x^3
2015-07-19 12:13 am
f(x)=2/x^2
f(x)=2x^-2
f'(x)=-4x^-3
Theres a 3 step lolz. idk
f(x)=2x^-2
f'(x)=-4x^-3
Theres a 3 step lolz. idk
2015-07-19 12:12 am
f(x) = 2x^(-2) --->f '(x) = -4x^(-3)=-4/x^3
收錄日期: 2021-05-02 11:15:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150718160816AApEcEb