Algebra help?
2015-06-28 1:39 pm
Find the 5th term of the sequence which has a first term of 1 and has a common ratio of 2.3. Round your answer to the nearest hundredth if necessary
回答 (7)
2015-06-28 2:43 pm
✔ 最佳答案
Series is a GP of form a, ar, ar^2,....,ar^(n-1),... where a is the first term, r is common ratio {|r| not 1} and thenth term is ar^(n-1), n = 1,2,3,...., ad inf. Here a = 1 and r = 2.5 and n = 5. So the 5th term is (1)(2.3)^4 =
27.9841, approx. = 27.98 to nearest one hundredth.
2015-06-28 2:05 pm
a₁ = 1
r = 2.3
a₅ = 2.3⁵⁻¹ = 27.9841 ≅ 27.98
r = 2.3
a₅ = 2.3⁵⁻¹ = 27.9841 ≅ 27.98
2015-06-28 2:02 pm
an=ar^(n-1) <--- that is the rule for a geometric sequence...
an=2.3^(n-1)
a(5)=2.3^4=27.98
an=2.3^(n-1)
a(5)=2.3^4=27.98
2015-06-28 1:57 pm
Fifth term = ar^4
= (1)(2.3)^4 = 27.9841
= (1)(2.3)^4 = 27.9841
2015-06-28 1:52 pm
a r^4 = 1 x 2.3^4 = 27.98
2015-06-28 1:49 pm
lol good luck mate i think you speak gibberish hothegow arethga yothegoo
2015-06-28 1:42 pm
2.3^4≈27.98
收錄日期: 2021-04-21 11:52:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150628053951AA88SYM