Consider 0=1/(1/0)
Left side is a number while right side is undefined, a contradiction. So, 1/0 must be defined.
What's wrong with this proof?
Simon YAU
http://ck-math.com
Defined=Undefined?
2015-06-12 2:35 am
回答 (3)
2015-06-12 7:59 am
✔ 最佳答案
1/0is undefined.
Hence, 1/(1/0) is undefined as the denominator is undefined.
Hence, 1/(1/0) ≠ 0
2015-06-21 7:28 pm
I know you have helped answer my question, thank you so much first.
But there is no one answering the question formally, so I deleted it.
Note that if you had answered it formally, you would have been chosen as the best answer giver.
Simon YAU.
But there is no one answering the question formally, so I deleted it.
Note that if you had answered it formally, you would have been chosen as the best answer giver.
Simon YAU.
2015-06-12 5:44 am
When you write A = B, both A and B needs to be defined.
Also, you cannot say a = 1/(1/a) for any a.
Problem solved.
2015-06-11 21:45:19 補充：
Only non-zero number can be applied to division operation as a divisor.
2015-06-21 01:22:08 補充：
Simon Yau, 為何你刪掉了最近發問的 limit of integral 那題目？？
(◕‿◕✿)
Also, you cannot say a = 1/(1/a) for any a.
Problem solved.
2015-06-11 21:45:19 補充：
Only non-zero number can be applied to division operation as a divisor.
2015-06-21 01:22:08 補充：
Simon Yau, 為何你刪掉了最近發問的 limit of integral 那題目？？
(◕‿◕✿)
收錄日期: 2021-04-16 16:52:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150611000051KK00068