代數與最小值 (2)

2015-06-03 3:20 am
設 P = (3 ‒ √3)ⁿ 而 n 為整數。若 P > 10⁹,求 n 的最小值。

回答 (1)

2015-06-03 3:40 am
✔ 最佳答案
(a)
(3 ‒ √3)ⁿ>10⁹
log(3 ‒ √3)ⁿ>log10⁹
n*log(3 ‒ √3)>9
n>9/log(3-√3)
n>87.29...
So, the smallest possible value of n is 88

(b)
If n=300, P=(3 ‒ √3)^300
10ⁿ⁻¹ < (3 ‒ √3)^300 < 10ⁿ
log10ⁿ⁻¹ < log(3 ‒ √3)^300 < log10ⁿ
n-1 < 300* log(3 ‒ √3) < n
n-1< 30.93 < n
So, n is 31


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