Chemistry help! Specific heat how to?
2015-06-01 4:51 am
What would be the final temperature of 50.0 g of H2O at 30.0 celcius was added to 40.0 g of H2O at 90.0 celcius? (Assume no loss of heat to the surroundings)
回答 (1)
2015-06-01 6:52 am
It's a weighted average:
((50.0 g x 30.0 °C) + (40.0 g x 90.0 °C)) / (50.0 g + 40.0 g) = 56.7 °C
((50.0 g x 30.0 °C) + (40.0 g x 90.0 °C)) / (50.0 g + 40.0 g) = 56.7 °C
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