A vessel of volume 0.42m^3 contains a mixture of 4.0g of hydrogen, 4.0g of helium and 12.0g of oxygen at a temperature of 320K. Find the pressure of the vessel.
( R=8.31J mol^-1 K^-1)
F.5 Physics gas
2015-05-29 7:26 am
回答 (1)
2015-05-29 8:35 am
✔ 最佳答案
No. of moles of hydrogen = 4/1 = 4No. of moles of helium = 4/4 = 1
No. of moles of oxygen = 12/16 = 0.75
Hence, total numbe rof moles = (4 + 1 + 0.75) = 5.75
Use ideal gas equation: PV = nRT
P.(0.42) = (5.75).(8.31).(320)
i.e. P = 36400 Pa = 36.4 kPa
2015-05-30 17:33:54 補充：
I go the information from the following web-page:
http://www.convertunits.com/molarmass/Oxygen
But I agree that, by default, the molecular molar mass should be used.
收錄日期: 2021-04-16 16:41:48
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150528000051KK00103