chemistry help!?

2015-05-27 5:43 pm
更新1:

One way to analyze for the amount of phosphorus in a rock is to precipitate the phosphorus as MgNH4PO4 which is then heated to turn it into Mg2P2O7. What weight of Mg2P2O7 will be obtained from a 2.558 g sample of a rock that contains 86.52% Ca3(PO4)2 (and no other source of phosphorus) if this analysis is done?

回答 (1)

2015-05-27 10:44 pm
(86.52% of 2.558 g Ca3(PO4)2) / (310.1767 g Ca3(PO4)2/mol) x (1 mol Mg2P2O7 / 1 mol Ca3(PO4)2) x
(222.5533 g Mg2P2O7/mol) = 1.588 g Mg2P2O7


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