Electrons traveling at a speed of 2.0 x 107 m/s?
2015-05-22 8:25 pm
Electrons traveling at a speed of 2.0 x 107 m/s to the left into a uniform magnetic field experience a deflecting force 3.0 x 10-13 N directed down the page. Calculate the strength and direction of the magnetic field.
回答 (2)
2015-05-22 8:26 pm
F = qvB
Plug in F, q and v. Solve for B.
Plug in F, q and v. Solve for B.
2015-05-22 8:45 pm
Hello Valery, of course friend Randy P has helped you by giving an expression. You just plug for q the charge of electron i.e. 1.6 * 10^-19 C
Direction has to be into the page in a perpendicular direction. Here we have to use Fleming's left hand rule. But due to negative charge of electron we can use right hand rule. So as thumb shows downward direction and middle finger the direction of electron ie getting into the field from left to right, then fore finger would give the direction of magnetic field. Hope you have understood all the details given to you. All the best
Direction has to be into the page in a perpendicular direction. Here we have to use Fleming's left hand rule. But due to negative charge of electron we can use right hand rule. So as thumb shows downward direction and middle finger the direction of electron ie getting into the field from left to right, then fore finger would give the direction of magnetic field. Hope you have understood all the details given to you. All the best
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