help coriolis effect

2015-05-19 7:08 am

At latitude 43(of the central Italy) where 2wsinφ is approximately equal to 10^-4 s-1, a motion of 10m/s would move in an inertia circle of 100 km radius completing an orbit in almost 14 hours.
HOW TO CALCULATE THAT?
why can't I just use period t=pi/(wsinφ)?
PLEASE HELP HELP

回答 (1)

天同

2015-05-19 11:36 pm

✔ 最佳答案

Radius of inertia circle R = v/f
where v is the speed of the motion, and f is the Coriolis parameter, which equals to 2.w.sin(φ)

Hence, the period T to complete an inertia circle with radius R is,
T = (2.pi.R)/v = (2.pi).(v/(2wsin(φ)).(1/v) =pi/(wsin(φ))

Substituting values of w = 2.pi/(24 x 3600) and φ = 43 degrees, T = 17.6 hours

Your "14 hours" seems to be underestimated.

You may refer to the following web-page. Read the section on "Inertia Circles".

http://en.wikipedia.org/wiki/Coriolis_effect

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