Which step can be used when solving x2- 6x - 25 = 0 by completing the square?

x² - 6x + 9 = 34
(x - 3)² = 34
x - 3 = ± √34
x = 3 ± √34

x^2 -6x = 25

ADD 9

x^2 -6x +9 =34

( x-3)^2 =34

x = 3+\/34 OR 3-\/34 ANSWER

x^2-6x-25=0 first move the constant to the other side by adding 25 to both sides

x^2-6x=25 now halve the linear coefficient, square it, add it to both sides...

x^2-6x+9=34 now we have a perfect square on the left side...

(x-3)^2=34 take the square root of both sides.

x-3=±34^(1/2) add three to both sides.

x=3±34^(1/2)

Thx

First one.

x^2-6x+9=36
(x-3)^2=36
x-3=+-6
x=-3 or 9