唔識做功課65

2015-05-06 10:59 pm
the cube of side 4cm. P is the point of intersection of the diagonals AC and BD. Find the angles between
a) PG and PE
b) PG and the plane ABGF
c) the planes ACG and ACE.

回答 (3)

2015-05-10 5:15 pm
✔ 最佳答案
你有冇答案嫁?係唔係 (a) 同 (c) 係同一個答案?

2015-05-10 09:15:27 補充:
(a) PG=PE=√(2²+2²+4²)=√24=2√6GE=√(4²+4²)=√32=4√2the angle between PG and PE is:∠EPG
=2 sin⁻¹(2√2 / 2√6)
=70.5° (corr. to 3 sf)
(b) The projection of PG to the plane ABGF is GX, where X is the mid-pt of AB.As PX=2, so,the angle between PG and the plane ABGF is:∠PGX=sin⁻¹(2 / 2√6)=24.1° (corr. to 3 sf)
(c) the angle between the planes ACG and ACE is:∠EPG=70.5° (corr. to 3 sf, from (a))
2015-05-10 7:33 pm
係呀!冇錯!唔該晒你...
2015-05-06 11:17 pm
我覺得呢題有圖會好少少 0.0


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